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Mathy=x^{1/2}/math math\dfrac{dy}{dx}=\dfrac{1}{2}x^{1/2}/math math\dfrac{dy}{dx}=\dfrac{1}{2x^{1/2}}/math math\dfrac{dy}{dx}=\dfrac{1}{2\sqrt{x}}/mathDomain of f (x) = x/ (x^21) WolframAlpha Area of a circle?N = f(x 1) x f(x 2) x f(x 3) x f(x n) x = 1 1 n2 1 n 1 2 2 n2 1 n 1 3 n 2 1 n 1 n2 n 1 n = 1 n 1 n 2 1 n 1 n 2 2 n2 1 n 1 n 32 n 1 n 1 n n n2 1 n = 4 5Finish the calculation above and nd A = lim n!1R n using the formula for the sum of squares and calculating the limit as if R n were a rational function with variable n
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EC02 Spring 06 HW5 Solutions 3 Problem 321 • The random variable X has probability density function fX (x) = ˆ cx 0 ≤ x ≤ 2, 0 otherwise2 If a < b, then F(a) ≤ F(b) for any real numbers a and b 163 Ex 12, 1 Show that the function f R* → R* defined by f(x) = 1/x is oneone and onto, where R* is the set of all nonzero real numbers Is the result true, if the domain R* is replaced by N with codomain being same as R*?




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Multivariable Calculus Sketch the contour map of f(x,y) = 1/(x^2 y^2) Label the level curves at c= 0, 1, 1/4, 4 We sketch the graph in three space toExample 1 Consider the joint PDF f X;Y (x;y) = 1 4 shown below Find the marginal PDFs Solution If we integrate over x and y, then we have f X(x) = 8 >< > 3;Then, f(x)g(x) = 4x 2 4x 1 = 1 Thus deg( f ⋅ g ) = 0 which is not greater than the degrees of f and g (which each had degree 1) Since the norm function is not defined for the zero element of the ring, we consider the degree of the polynomial f ( x ) = 0 to also be undefined so that it follows the rules of a norm in a Euclidean domain



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The cdf of random variable X has the following properties F X ( t) is a nondecreasing function of t, for − ∞ < t < ∞ The cdf, F X ( t), ranges from 0 to 1 This makes sense since F X ( t) is a probability If X is a discrete random variable whose minimum value is a, then F X ( a) = P ( X ≤ a) = P ( X = a) = f X lim_(x rarr 1)(x^21)/(x1) = 2 Let f(x) = (x^21)/(x1) then f(x) is defined everywhere except at x=1, however when we evaluate the limit we are not interested in the value of f(1), just the behaviour of f(c) for c close to 1Calculus Derivatives Limit Definition of Derivative 1 Answer



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Given f (x) = 3x 2 – x 4, find the simplified form of the following expression, and evaluate at h = 0 This isn't really a functionsoperations question, but something like this often arises in the functionsoperations contextGiven f (x) = x 2 2x – 1, find f (2) To evaluate f (x) at x = 2, I'll plug 2 in for every instance of x in the function's rule f (2) = (2) 2 2(2) – 1 To keep things straight in my head (and clear in my working), I've put parentheses around every instance of the argument 2 in the formula for f Now I Given, f(x) = (x 1) 3 (x 2) 2 On differentiating both sides wrt x, we get Now, we find intervals and check in which interval f(x) is strictly increasing and strictly decreasing




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